\(\dfrac{3}{4}-\dfrac{4}{9}.\dfrac{27}{16}=\dfrac{3}{4}\left(1-\dfrac{4}{9}.\dfrac{9}{4}\right)=\dfrac{3}{4}.\left(1-1\right)=0\)
\(\dfrac{3}{4}\) - \(\dfrac{4}{9}\).\(\dfrac{27}{16}\)= \(\dfrac{3}{4}\)-\(\dfrac{3}{4}\)=0
\(\dfrac{3}{4}-\dfrac{4}{9}\cdot\dfrac{27}{16}=\dfrac{3}{4}-\left(\dfrac{4}{9}\cdot\dfrac{27}{16}\right)=\dfrac{3}{4}-\dfrac{2}{3}=\dfrac{1}{12}\)
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