PT: \(H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O\)
Ta có: \(n_{Na_2SO_4}=\dfrac{2,6128}{142}=0,0184\left(mol\right)\)
Theo PT: \(n_{H_2SO_4}=n_{Na_2SO_4}=0,0184\left(mol\right)\)
\(\Rightarrow m_{H_2SO_4}=0,0184.98=1,8032\left(g\right)\)
\(\Rightarrow D_{H_2SO_4}=\dfrac{1,8032}{1}=1,8032\left(g/cm^3\right)\)
Bạn tham khảo nhé!