\(m_{CH_3COOH}=100.30\%=30\left(g\right)\Rightarrow n_{CH_3COOH}=\dfrac{30}{60}=0,5\left(mol\right)\)
PT: \(CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O\)
Theo PT: \(n_{NaOH}=n_{CH_3COOH}=0,5\left(mol\right)\)
\(\Rightarrow m_{ddNaOH}=\dfrac{0,5.40}{20\%}=100\left(g\right)\)