\(\left(\dfrac{1}{3}+\dfrac{5}{1}\right)\times\dfrac{1}{2}=\dfrac{16}{3}\times\dfrac{1}{2}=\dfrac{16}{6}=\dfrac{8}{3}\)
\(\left(\dfrac{1}{3}+\dfrac{5}{1}\right)\times\dfrac{1}{2}=\left(\dfrac{1}{2}\times\dfrac{1}{3}\right)+\left(\dfrac{1}{2}\times5\right)=\dfrac{1}{6}+\dfrac{5}{2}=\dfrac{8}{3}\)
câu b dựa theo làm nha bạn