\(\dfrac{\left(-\dfrac{2}{7}\right).\dfrac{5}{11}+\left(-\dfrac{2}{7}\right).\dfrac{6}{11}}{\dfrac{4}{7}}=\dfrac{-\dfrac{2}{7}.\left(\dfrac{5}{11}+\dfrac{6}{11}\right)}{\dfrac{4}{7}}=\dfrac{-\dfrac{2}{7}}{\dfrac{4}{7}}=\dfrac{-2}{7}.\dfrac{7}{4}=\dfrac{-2}{4}=-\dfrac{1}{2}\)