Ta có : \(\left|x-1\right|+\left|x-2\right|=x-3\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-1+x-2=x-3\\x-1+x-2=-x-3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+x-x=1+2-3\\x+x+x=1+2-3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\3x=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=0\end{matrix}\right.\)
Vậy \(x=0\)