\(x-3=xy+2y\)
\(\Rightarrow xy+2y-x+3=0\)
\(\Rightarrow xy+2x-x-2=-5\)
\(\Rightarrow x\left(y+2\right)-1\left(x+2\right)=-5\)
\(\Rightarrow\left(x-1\right)\left(y+2\right)=-5\)
Xét ước:v
Ta có : \(xy+2y-x+3=0\)
\(\Leftrightarrow y\left(x+2\right)-\left(x+2\right)+5=0\)
\(\Leftrightarrow\left(x+2\right)\left(y-1\right)=-5\)
Rồi xét ước nha bạn.