Question

Tìm \(x\), biết :

a) \(\dfrac{3}{4}x=1\)                        b) \(\dfrac{4}{7}x=\dfrac{9}{8}-0,125\)

Answer 1

a) \(\dfrac{3}{4}x=1\)

\(x=1:\dfrac{3}{4}\)

\(x=1.\dfrac{4}{3}\)

\(x=\dfrac{4}{3}\)

b)\(\dfrac{4}{7}x=\dfrac{9}{8}-0,125\)

\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\)

\(\dfrac{4}{7}x=1\)

\(x=1:\dfrac{4}{7}\)

\(x=1.\dfrac{7}{4}\)

\(x=\dfrac{7}{4}\)

Answer 2

a) \(\dfrac{3}{4}x=1\)

\(x=1:\dfrac{3}{4}=1.\dfrac{4}{3}\)

\(x=\dfrac{4}{3}\)

Vậy \(x=\dfrac{4}{3}\)

b) \(\dfrac{4}{7}x=\dfrac{9}{8}-0,125\)

\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\)

\(\Rightarrow\dfrac{4}{7}x=1\)

\(x=1:\dfrac{4}{7}=1.\dfrac{7}{4}\)

\(x=\dfrac{7}{4}\)

Vậy \(x=\dfrac{7}{4}\)