Ta có:
\(2x-1⋮x+3\)
\(\Rightarrow\left(2x+6\right)-7⋮x+3\)
\(\Rightarrow2\left(x+3\right)-7⋮x+3\)
\(\Rightarrow-7⋮x+3\)
\(\Rightarrow x+3\in\left\{1;7\right\}\text{ ( vì x là số tự nhiên )}\)
+) \(x+3=1\Rightarrow x=-2\left(loai\right)\)
+) \(x+3=7\Rightarrow x=4\left(thoa\right)\)
Vậy x=4