50%+\(\dfrac{2}{3}\)x = x+4
=>\(\dfrac{1}{2}\)+\(\dfrac{2}{3}\)x = x+4
=>\(\dfrac{2}{3}\)x-x=4-\(\dfrac{1}{2}\)
=>\(\dfrac{-1}{3}\)x = \(\dfrac{7}{2}\)
=> x = -10,5
\(50\%+\dfrac{2}{3}x=x+4\Rightarrow\dfrac{1}{2}+\dfrac{2}{3}x=x+4\)
\(\Rightarrow\dfrac{2}{3}x-x=4+\dfrac{1}{2}\Rightarrow\dfrac{-1}{3}x=\dfrac{9}{2}\)
\(\Rightarrow x=\dfrac{9}{2}.\left(-3\right)=\dfrac{-27}{2}\)
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