27 tháng 12 2020 lúc 16:00
Bài 1: Căn bậc hai
Các câu hỏi tương tự
Rút gọn các biểu thức saua,Aleft(dfrac{1}{x-sqrt{x}}+dfrac{1}{sqrt{x}-1}right):dfrac{sqrt{x}+1}{x-2sqrt{x}+1}b,Bdfrac{2sqrt{x}-1}{sqrt{x}+1}+dfrac{3sqrt{x}-1}{x-sqrt{x}+1}-dfrac{2xsqrt{x}-2x+2sqrt{x}-3}{xsqrt{x}+1}c,Cleft(1-dfrac{x+3sqrt{x}}{x-9}right):left(dfrac{sqrt{x}-3}{2-sqrt{x}}+dfrac{sqrt{x}-2}{3+sqrt{x}}-dfrac{9-x}{x+sqrt{x}-6}right)d,Dleft(dfrac{sqrt{x}}{3+sqrt{x}}+dfrac{x+9}{9-x}right):left(dfrac{3sqrt{x}+1}{x-3sqrt{x}}-dfrac{1}{sqrt{x}}right)e,Edfrac{15sqrt{x}-11}{x+2sqrt{x}-3}+dfrac{...
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Rút gọn các biểu thức sau
a,\(A=\left(\dfrac{1}{x-\sqrt{x}}+\dfrac{1}{\sqrt{x}-1}\right):\dfrac{\sqrt{x}+1}{x-2\sqrt{x}+1}\)
b,\(B=\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}+\dfrac{3\sqrt{x}-1}{x-\sqrt{x}+1}-\dfrac{2x\sqrt{x}-2x+2\sqrt{x}-3}{x\sqrt{x}+1}\)
c,\(C=\left(1-\dfrac{x+3\sqrt{x}}{x-9}\right):\left(\dfrac{\sqrt{x}-3}{2-\sqrt{x}}+\dfrac{\sqrt{x}-2}{3+\sqrt{x}}-\dfrac{9-x}{x+\sqrt{x}-6}\right)\)
d,\(D=\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}+\dfrac{x+9}{9-x}\right):\left(\dfrac{3\sqrt{x}+1}{x-3\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right)\)
e,\(E=\dfrac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\dfrac{3\sqrt{x}-2}{1-\sqrt{x}}-\dfrac{2\sqrt{x}+3}{\sqrt{x}+3}\)
Cho x = \(5+4\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}\)
Tính A = \(\dfrac{x^2-\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{2x+\sqrt{x}}{\sqrt{x}}+\dfrac{2\left(x-1\right)}{\sqrt{x}-1}\)
a) \(\sqrt{\dfrac{x^2-2x+1}{x+2\sqrt{x}+1}}\)
b)\(\dfrac{x-1}{\sqrt{y}-1}.\sqrt{\dfrac{\left(y-2\sqrt{y}+1\right)^2}{\left(x-1\right)^4}}\)
1. Tính:
sqrt{dfrac{x-1+sqrt{2x-3}}{x+2-sqrt{2x+3}}}
2. Chứng minh:
a) dfrac{left(3sqrt{xy}-6y.2xsqrt{y}+4ysqrt{x}right)left(3sqrt{y}+2sqrt{xy}right)}{yleft(sqrt{x}-2sqrt{y}right)left(y-4xright)}1
b) left(sqrt{x}-sqrt{y}-dfrac{sqrt{xy}}{sqrt{x}+sqrt{y}}right)left(dfrac{sqrt{x}}{sqrt{x}+sqrt{y}}+dfrac{y}{sqrt{x}-sqrt{y}}-dfrac{2sqrt{xy}}{xy}right)sqrt{x}+sqrt{y}
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1. Tính:
\(\sqrt{\dfrac{x-1+\sqrt{2x-3}}{x+2-\sqrt{2x+3}}}\)
2. Chứng minh:
a) \(\dfrac{\left(3\sqrt{xy}-6y.2x\sqrt{y}+4y\sqrt{x}\right)\left(3\sqrt{y}+2\sqrt{xy}\right)}{y\left(\sqrt{x}-2\sqrt{y}\right)\left(y-4x\right)}=1\)
b) \(\left(\sqrt{x}-\sqrt{y}-\dfrac{\sqrt{xy}}{\sqrt{x}+\sqrt{y}}\right)\left(\dfrac{\sqrt{x}}{\sqrt{x}+\sqrt{y}}+\dfrac{y}{\sqrt{x}-\sqrt{y}}-\dfrac{2\sqrt{xy}}{xy}\right)=\sqrt{x}+\sqrt{y}\)
Bài 1: Pdfrac{sqrt{x}+1}{x-1}-dfrac{x+2}{xsqrt{x}-1}-dfrac{sqrt{x}+1}{x+sqrt{x}+1}
a.Rút gọn P
b, Tìm MaxQ dfrac{2}{P}+sqrt{x}
Bài 2:
Pleft(1-dfrac{1-3sqrt{x}}{x-9}right):left(dfrac{9-x}{x+sqrt{x}+6}-dfrac{sqrt{x}-3}{2-sqrt{x}}-dfrac{sqrt{x}-3}{sqrt{x}+3}right)
a, Rút gọn P
b, Tìm x để P 0
c, Max Q P(x+1)
Bài 3:Pdfrac{x-sqrt{x}}{x+sqrt{x}+1}-dfrac{2x+sqrt{x}}{sqrt{x}}+dfrac{2left(x-1right)}{sqrt{x}-1}
a, Rút gọn P
b, Tìm x để Qdfrac{2sqrt{x}}{P} nhận giá trị nguyên
Bài 4: Rút gọn:...
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Bài 1: \(P=\dfrac{\sqrt{x}+1}{x-1}-\dfrac{x+2}{x\sqrt{x}-1}-\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}\)
a.Rút gọn P
b, Tìm MaxQ = \(\dfrac{2}{P}+\sqrt{x}\)
Bài 2:
\(P=\left(1-\dfrac{1-3\sqrt{x}}{x-9}\right):\left(\dfrac{9-x}{x+\sqrt{x}+6}-\dfrac{\sqrt{x}-3}{2-\sqrt{x}}-\dfrac{\sqrt{x}-3}{\sqrt{x}+3}\right)\)
a, Rút gọn P
b, Tìm x để P > 0
c, Max Q = P(x+1)
Bài 3:\(P=\dfrac{x-\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{2x+\sqrt{x}}{\sqrt{x}}+\dfrac{2\left(x-1\right)}{\sqrt{x}-1}\)
a, Rút gọn P
b, Tìm x để \(Q=\dfrac{2\sqrt{x}}{P}\) nhận giá trị nguyên
Bài 4: Rút gọn: \(P=\left(2-\dfrac{\sqrt{x}-1}{2\sqrt{x}-3}\right):\left(\dfrac{6\sqrt{x}+1}{2x-\sqrt{x}-3}+\dfrac{\sqrt{x}}{\sqrt{x+1}}\right)\)
16 tháng 6 2021 lúc 16:12
\(A=\left(\dfrac{1}{1-\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right):\left(\dfrac{2x+\sqrt{x}-1}{1-x}+\dfrac{2x\sqrt{x}+x-\sqrt{x}}{1+x\sqrt{x}}\right)\)
a) Rút gọn biểu thức
b) Tính GTBT A khi x = 17 - 12√2
Tính giá trị của P = \(\left(\dfrac{\sqrt{x-1}}{3+\sqrt{x-1}}+\dfrac{x+8}{10-x}\right):\left(\dfrac{3\sqrt{x-1}+1}{x-3\sqrt{x-1}-1}-\dfrac{1}{\sqrt{x-1}}\right)\)khi x=\(\sqrt[4]{\dfrac{3+2\sqrt{2}}{3-2\sqrt{2}}}-\sqrt[4]{\dfrac{3-2\sqrt{2}}{3+2\sqrt{2}}}\)
\(\sqrt{\dfrac{x+2}{4}}+\sqrt{25x+50}-2\sqrt{x+2}=14\) ; \(\sqrt{2x+3}=x\) ; \(\sqrt{25x^2+20x+4}=1\) ; \(\sqrt{\dfrac{x+1}{2x-1}}=2\) ; \(\dfrac{\sqrt{x-2}}{\sqrt{3x+1}}=6\)
Tìm x
A=\(\left(\dfrac{\sqrt{x}-2}{x-1}-\dfrac{\sqrt{x}+2}{x+2\sqrt{x}+1}\right).\dfrac{x^2-2x+1}{2}\)