Bài 8: Rút gọn biểu thức chứa căn bậc hai
Các câu hỏi tương tự
Q = \(\left(\frac{\sqrt{6}-\sqrt{2}}{1-\sqrt{3}}-\frac{5}{\sqrt{5}}\right).\left(\sqrt{5}-\sqrt{2}\right)\)
R = \(\frac{2}{7+4\sqrt{3}}+\frac{2}{7-4\sqrt{3}}\)
S = \(\frac{2}{\sqrt{5}+1}-\sqrt{\frac{2}{3-\sqrt{5}}}\)
T = \(\frac{4}{1-\sqrt{3}}-\frac{\sqrt{15}+\sqrt{3}}{1+\sqrt{5}}\)
J left(1+frac{2+sqrt{2}}{1+sqrt{2}}right) . left(1-frac{2-sqrt{2}}{1-sqrt{2}}right)
M frac{3sqrt{2}-2sqrt{3}}{sqrt{3}-sqrt{2}}:frac{1}{sqrt{6}}
N frac{6}{1+sqrt{7}}+frac{1}{sqrt{7}}
O frac{3+2sqrt{3}}{sqrt{3}}+frac{2+sqrt{2}}{1+sqrt{2}}-frac{1}{2-sqrt{3}}
Q left(frac{sqrt{6}-sqrt{2}}{1-sqrt{3}}-frac{5}{sqrt{5}}right).left(sqrt{5}-sqrt{2}right)
S frac{2}{sqrt{5}+1}-sqrt{frac{2}{3-sqrt{5}}}
Các thầy cô, các bạn giúp em với ạ. Em cảm ơn !
Đọc tiếp
J = \(\left(1+\frac{2+\sqrt{2}}{1+\sqrt{2}}\right)\) . \(\left(1-\frac{2-\sqrt{2}}{1-\sqrt{2}}\right)\)
M = \(\frac{3\sqrt{2}-2\sqrt{3}}{\sqrt{3}-\sqrt{2}}:\frac{1}{\sqrt{6}}\)
N = \(\frac{6}{1+\sqrt{7}}+\frac{1}{\sqrt{7}}\)
O = \(\frac{3+2\sqrt{3}}{\sqrt{3}}+\frac{2+\sqrt{2}}{1+\sqrt{2}}-\frac{1}{2-\sqrt{3}}\)
Q = \(\left(\frac{\sqrt{6}-\sqrt{2}}{1-\sqrt{3}}-\frac{5}{\sqrt{5}}\right).\left(\sqrt{5}-\sqrt{2}\right)\)
S = \(\frac{2}{\sqrt{5}+1}-\sqrt{\frac{2}{3-\sqrt{5}}}\)
Các thầy cô, các bạn giúp em với ạ. Em cảm ơn !
Đề bài: Thực hiện phép tính :
a) left(frac{2sqrt{3}-sqrt{6}}{sqrt{8}-2}-frac{sqrt{216}}{3}right).frac{1}{sqrt{6}}
b) left(frac{sqrt{14}-sqrt{7}}{1-sqrt{2}}-frac{sqrt{15}-sqrt{5}}{1-sqrt{3}}right):frac{1}{sqrt{7}+sqrt{5}}
c) frac{sqrt{5+2sqrt{6}}+sqrt{8-2sqrt{15}}}{sqrt{7+2sqrt{10}}}
Giúp em với ạ, em cảm ơn !
Đọc tiếp
Đề bài: Thực hiện phép tính :
a) \(\left(\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}-\frac{\sqrt{216}}{3}\right).\frac{1}{\sqrt{6}}\)
b) \(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}-\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}+\sqrt{5}}\)
c) \(\frac{\sqrt{5+2\sqrt{6}}+\sqrt{8-2\sqrt{15}}}{\sqrt{7+2\sqrt{10}}}\)
Giúp em với ạ, em cảm ơn !
A) 2sqrt{3}+sqrt{48}-sqrt{75}-sqrt{243}
b) left(frac{sqrt{7}-sqrt{14}}{1-sqrt{2}}+frac{sqrt{15}-sqrt{5}}{1-sqrt{3}}right):frac{1}{sqrt{7}+sqrt{5}}
c) left(sqrt{3}+1right)sqrt{4-2sqrt{3}}
d) 5sqrt{2}+sqrt{18}-sqrt{98}-sqrt{288}
e)left(frac{sqrt{3}-sqrt{6}}{1-sqrt{2}}+frac{sqrt{15}-sqrt{5}}{1-sqrt{3}}right):frac{1}{sqrt{3}+sqrt{5}}
g)left(sqrt{3}-1right)sqrt{4+2sqrt{3}}
Đọc tiếp
A) \(2\sqrt{3}+\sqrt{48}-\sqrt{75}-\sqrt{243}\)
b) \(\left(\frac{\sqrt{7}-\sqrt{14}}{1-\sqrt{2}}+\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}+\sqrt{5}}\)
c) \(\left(\sqrt{3}+1\right)\sqrt{4-2\sqrt{3}}\)
d) \(5\sqrt{2}+\sqrt{18}-\sqrt{98}-\sqrt{288}\)
e)\(\left(\frac{\sqrt{3}-\sqrt{6}}{1-\sqrt{2}}+\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{3}+\sqrt{5}}\)
g)\(\left(\sqrt{3}-1\right)\sqrt{4+2\sqrt{3}}\)
so sánh:
\(\sqrt{7}-\sqrt{5}và\sqrt{5}-\sqrt{3}\)
\(\frac{1}{3}\sqrt{6}và6\sqrt{\frac{1}{3}}\)
\(\frac{5\sqrt{3}}{\sqrt{3-\sqrt{5}}-\sqrt{3}}-\frac{5\sqrt{3}}{\sqrt{3-\sqrt{5}}+\sqrt{3}}\)
\(\frac{a}{a-2\sqrt{b}}\)
\(\frac{\sqrt{b}+b\sqrt{a}}{\sqrt{a}+\sqrt{b}}\)
Rút gọn
A= \(\frac{8+2\sqrt{15}+\sqrt{21}+\sqrt{35}}{\sqrt{3}+\sqrt{5}+\sqrt{7}}\)
B= \(\frac{1}{\sqrt{1}+\sqrt{2}}\)+\(\frac{1}{\sqrt{2}+\sqrt{3}}\)+\(\frac{1}{\sqrt{3}+\sqrt{4}}\)+\(\frac{1}{\sqrt{4}+\sqrt{5}}\)+\(\frac{1}{\sqrt{5}+\sqrt{6}}\)
rút gọn
A= \(\frac{\sqrt{3}+\sqrt{5}}{\sqrt{3}-\sqrt{5}}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\)
B= \(\frac{5+2\sqrt{5}}{\sqrt{5}}+\frac{3+\sqrt{3}}{\sqrt{3}}-\left(\sqrt{5}+\sqrt{3}\right)\)
1 .
a)Afrac{2}{2sqrt[3]{2}+2+sqrt[3]{4}}
b)Bfrac{6}{2sqrt[3]{2}-2+sqrt[3]{4}}
c)Cfrac{2}{sqrt[3]{4}+sqrt[3]{2}+2}
2 .
a)Asqrt{sqrt{5}-sqrt{3-sqrt{29-12sqrt{5}}}}
b)Bfrac{left(5+2sqrt{6}right).left(49-20sqrt{6}right).sqrt{5-2sqrt{6}}}{9sqrt{3}-11sqrt{2}}
c)Csqrt{4+sqrt{5sqrt{3}+5sqrt{48-10sqrt{7}+4sqrt{3}}}}
d)D(left(sqrt{3}-1right).sqrt{6+2sqrt{2}.sqrt{3-sqrt{sqrt{2}+sqrt{12}+sqrt{18-sqrt{128}}}}}
Đọc tiếp
1 .
a)\(A=\frac{2}{2\sqrt[3]{2}+2+\sqrt[3]{4}}\)
b)\(B=\frac{6}{2\sqrt[3]{2}-2+\sqrt[3]{4}}\)
c)C=\(\frac{2}{\sqrt[3]{4}+\sqrt[3]{2}+2}\)
2 .
a)\(A=\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
b)\(B=\frac{\left(5+2\sqrt{6}\right).\left(49-20\sqrt{6}\right).\sqrt{5-2\sqrt{6}}}{9\sqrt{3}-11\sqrt{2}}\)
c)C=\(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7}+4\sqrt{3}}}}\)
d)D=(\(\left(\sqrt{3}-1\right).\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{\sqrt{2}+\sqrt{12}+\sqrt{18-\sqrt{128}}}}}\)