Question

Rút gọn biểu thức: \(\sqrt{2\left(a^2-b^2\right)}.\sqrt{\dfrac{3}{a+b}}\) với (a ≥ b > 0).

Answer 1

\(\begin{array}{l}\sqrt {2\left( {{a^2} - {b^2}} \right)} .\sqrt {\frac{3}{{a + b}}} \\ = \sqrt {2\left( {{a^2} - {b^2}} \right).\frac{3}{{a + b}}} \\ = \sqrt {2\left( {a - b} \right)\left( {a + b} \right)\frac{3}{{a + b}}} \\ = \sqrt {6\left( {a - b} \right)} \end{array}\)