a) \(\dfrac{4116-14}{10290-35}=\dfrac{4102}{10255}=\dfrac{2051.2}{2051.5}=\dfrac{2}{5}\)
b) \(\dfrac{2929-101}{2.1919+404}=\dfrac{2929-101}{3838+404}=\dfrac{2828}{4242}=\dfrac{1414.2}{1414.3}=\dfrac{2}{3}\)
Rút gọn :
A= \(\dfrac{4116-14}{10290-35}\)= \(\dfrac{4102}{10255}=\dfrac{4102:2051}{10255:2051}=\dfrac{2}{5}\)
B=\(\dfrac{2929-101}{2.1919+404}=\dfrac{2828}{3838+404}=\dfrac{2828}{4242}=\dfrac{2828:1414}{4242:1414}=\dfrac{2}{3}\)