Ta có:
\(m_{CuSO4}=200.10\%=20\left(g\right)\)
\(\Rightarrow n_{CuSO4}=\frac{20}{160}=0,125\left(mol\right)\)
\(CuSO_4+2NaOH\rightarrow Cu\left(OH\right)_2+Na_2SO_4\)
0,125 ______________0,125_________________
\(Cu\left(OH\right)_2\rightarrow CuO+H_2O\)
0,125_________ 0,125___________
\(\Rightarrow m=m_{CuO}=0,125.80=10\left(g\right)\)