b, Ta có \(\dfrac{V_{N2}}{V_{O2}}=\dfrac{1}{3}\)
mà VN2 + VO2 = 8,96
=> VN2 = 8,96 - VO2
=> \(\dfrac{8,96-V_{O2}}{V_{O2}}=\dfrac{1}{3}\)
=> VO2 = 6,72 ( lít )
=> nO2 = 6,72 : 22,4 = 0,3 ( mol )
=> mO2 = 0,3 . 32 = 9,6 ( gam )
=> VN2 = 8,96 - 6,72 = 2,24 ( lít )
=> nN2 = 2,24 : 22,4 = 0,1 ( mol )
=> mN2 = 0,1 . 28 = 2,8 ( gam )