nCO2=0,25(mol)
nO2=0,5(mol)
nN2=0,7(mol)
nH2=0,4(mol)
a;
\(\sum\)nX=0,25+0,5+0,7+0,4=1,85(mol)
b;
\(\sum\)mX=0,25.44+32.0,5+0,7.28+0,4.2=47,4(g)
c;
\(\sum\)VX=5,6+11,2+15,68+8,96=41,44(lít)
%VCO2=\(\dfrac{5,6}{41,44}.100\%=13,5\%\)
%VO2=\(\dfrac{11,2}{41,44}.100\%=27\%\)
%VN2=\(\dfrac{15,68}{41,44}.100\%=37,8\%\)
%VH2=100-37,8-27-13,5=21,7%