Giả sử mZn = mAl = a (g)
\(n_{Zn}=\dfrac{a}{65}\left(mol\right)\); \(n_{Al}=\dfrac{a}{27}\left(mol\right)\)
PTHH: Zn + H2SO4 --> ZnSO4 + H2 (1)
=> \(n_{H_2\left(1\right)}=\dfrac{a}{65}\left(mol\right)\)
2Al + 3H2SO4 -->Al2(SO4)3 + 3H2
=> \(n_{H_2\left(2\right)}=\dfrac{a}{18}\left(mol\right)\)
Có \(n_{H_2\left(1\right)}< n_{H_2\left(2\right)}\)
=> Nhôm cho nhiều H2 hơn