\(2CuO+C-->2Cu+CO2\)
x-----------------------x-----------0,5x(mol)
\(2Fe2O3+3C-->4Fe+3CO2\)
y-------------------------2y---------1,5y(mol)
\(n_{CO2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
Theo bài ta có hpt
\(\left\{{}\begin{matrix}64x+112y=4\\0,5x+1,5y=0,2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\\\end{matrix}\right.\)
Đề sai j k bạn