MA = 4,034.29 = 117(g/mol)
\(m_C=\dfrac{51,28.117}{100}=60\left(g\right)=>n_C=\dfrac{60}{12}=5\left(mol\right)\)
\(m_H=\dfrac{9,4.117}{100}=11\left(g\right)=>n_H=\dfrac{11}{1}=11\left(mol\right)\)
\(m_N=\dfrac{11,97.117}{100}=14\left(g\right)=>n_N=\dfrac{14}{14}=1\left(mol\right)\)
\(m_O=117-60-11-14=32\left(g\right)=>n_O=\dfrac{32}{16}=2\left(mol\right)\)
=> CTPT: C5H11NO2