goi x la so mol cua Al
y la so mol cua Mg
\(n_{H_2}=\dfrac{8,96}{22,4}=0,4\left(mol\right)\)
2Al + 6HCl \(\rightarrow\) 2AlCl3 + 3H2
de: x \(\rightarrow\) 3x \(\rightarrow\) x \(\rightarrow\) 1,5x
Mg + 2HCl \(\rightarrow\) MgCl2 + H2
de: y \(\rightarrow\) 2y \(\rightarrow\) y \(\rightarrow\) y
Ta co: 27x + 24y = 7,8
1,5x + y = 0,4
=> x = 0,2 ; y = 0,1
a, \(m_{Al}=0,2.27=5,4g\)
\(\%m_{Al}=\dfrac{5,4}{7,8}.100\%\approx69,23\%\)
\(\%m_{Mg}=100-69,23\approx30,77\%\)
b, \(m_{HCl}=36,5.\left(0,2.3+0,1.2\right)=29,2g\)
\(m_{ddHCl}=\dfrac{29,2}{14,6}.100=200g\)
c+ d , \(m_{AlCl_3}=0,2.133,5=26,7g\)
\(m_{MgCl_2}=0,1.95=9,5g\)
\(m_{ddY}=26,7+9,5=36,2g\)
\(m_{ddspu}=200+7,8=207,8g\)
\(C\%_{AlCl_3}=\dfrac{26,7}{207,8}.100\%\approx12,85\%\)
\(C\%_{MgCl_2}=\dfrac{9,5}{207,8}.100\%\approx4,5\%\%\)
Chào bạn, bài bạn cần mình có làm ở đây nhé!
Hóa 9
