nSO2 = 0,2 mol
nNaOH = 0,3 mol
Ta có
\(\dfrac{n_{NaOH}}{n_{SO2}}\) = \(\dfrac{0,3}{0,2}\) = 1,5
\(\Rightarrow\) tạo 2 muối
2NaOH + SO2 \(\rightarrow\)Na2SO3 + H2O
x................0,5x.......0,5x
NaOH + SO2 \(\rightarrow\) NaHSO3
y..............y.............y
Ta có hệ
\(\left\{{}\begin{matrix}x+y=0,3\\0,5x+y=0,2\end{matrix}\right.\)
\(\Rightarrow\) \(\left\{{}\begin{matrix}x=0,2\\y=0,1\end{matrix}\right.\)
\(\Rightarrow\) mNa2SO3 = 0,2.126 = 25,2 (g)
\(\Rightarrow\) mNaHSO3 = 0,1.104 = 10,4 (g)