a, \(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\)
Hspt: _____1_____2 ________1 _____1 (mol)
Pư: _______ 0,2____ 0,4_______ 0,2 ___ 0,2 (mol)
\(n_{Zn}=\frac{13}{65}=0,2\left(mol\right)\)
\(m_{ZnCl2}=n_{ZnCl2}+M_{ZnCl2}\)
\(=0,2.\left(65+35,5.2\right)=27,2\left(g\right)\)
\(m_{HCl}=n_{HCl}+M_{HCl}\)
\(=0,4.\left(1+35,5\right)=14,6\left(g\right)\)
a. PTHH:
Zn+2HCl—>ZnCl2+H2
b.nZn = \(\frac{13}{65}\)= 0,2(mol)
Tỉ lệ: 1 : 2 : 1 : 1
Bài ra:0,2 mol—>0,2 mol
mZnCl2 = 0,2.136 = 27,2(g)
c.bài ra 0,2mol—>0,4mol
mHCl=(1+35,5).0,4=14,6(mol)
Nhầm 14,6g nhé
