Question

Hãy cho biết số mol của những khối lượng chất sau

a) 6 gam C ; 0,124 gam P ; 42gam Fe

b ) 3,6 gam H2O ; 95,48 gam CO2 ; 29,25 gam NaCl

Cần gấp nha !!!!

Answer 1

a, nC=6/12=0,5

nP=0,124/31=0,004

nFe= 42/56=0,75

b, nH2O=3,6/18=0,2

nCO2= 95,48/44=2,17

nNaCl=29,25/58,5=0,5

Answer 2

a, nC= 6/12=0,5(mol)
nP= 0,124/31=1/250(mol)
nFe=42/560,75(mol)
b,nH2O=3,6/180,2(mol)
nCO2=95,48/44=2,17(mol)
nNaCl=29,25/258,5=0,1131528046(mol)

Answer 3

a) \(n_C=\dfrac{6}{12}=0,5\left(mol\right)\)

\(n_P=\dfrac{0,124}{31}=0,004\left(mol\right)\)

\(n_{Fe}=\dfrac{42}{56}=0,75\left(mol\right)\)

b) \(n_{H_2O}=\dfrac{3,6}{18}=0,2\left(mol\right)\)

\(n_{CO_2}=\dfrac{95,48}{44}=2,17\left(mol\right)\)

\(n_{NaCl}=\dfrac{29,25}{58,5}=0,5\left(mol\right)\)