\(=\dfrac{\left(x^2-y^2\right)\left(x^2+y^2\right)\left(x-y\right)}{\left(x-y\right)^2x\left(x+y\right)}=\dfrac{\left(x-y\right)^2\left(x+y\right)\left(x^2+y^2\right)}{x\left(x-y\right)^2\left(x+y\right)}=\dfrac{x^2+y^2}{x}\)
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