\(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)
\(\Leftrightarrow\dfrac{12x-2\left(5x+2\right)}{12}=\dfrac{3\left(7-3x\right)}{12}\)
\(\Leftrightarrow\dfrac{12x-10x-4}{12}=\dfrac{21-9x}{12}\)
\(\Leftrightarrow12x-10x-4=21-9x\)
\(\Leftrightarrow12x-10x+9x=21+4\)
\(\Leftrightarrow11x=25\)
\(\Leftrightarrow x=\dfrac{25}{11}\)
Vậy phương trình có nghiệm duy nhất \(x=\dfrac{25}{11}\)
\(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)
\(\Leftrightarrow\dfrac{12x}{12}-\dfrac{2\left(5x+2\right)}{12}=\dfrac{3\left(7-3x\right)}{12}\)
\(\Leftrightarrow12x-10x-4=21-9x\)
\(\Leftrightarrow12x-10x+9x=4+21\)
\(\Leftrightarrow11x=25\)
\(\Leftrightarrow x=\dfrac{25}{11}\)
Tập nghiệm của phương trình S = \(\left\{\dfrac{25}{11}\right\}.\)
