a)
nSO2=3,36 / 22,4=0,15 mol
Cu +2H2SO4 đ -t°-> CuSO4+SO2+2H2O
=> nCu = nSO2 = CuSO4 = 0,15 mol
mCuSO4=0,15.160=24g
mZnSO4=56,2-24=32,2g
nZnSO4=nZnO= 32,2/161=0,2 mol
m=mCu+mZnO=0,15.64+0,2.81=25,8g
b)
nH2SO4 pư=2nCu+nZnO=2.0,15+0,2=0,5 mol
nH2SO4 dư=0,5.10%=0,05mol
H2SO4+BaCl2 -> BaSO4+2HCl
nH2SO4dư=nBaSO4=0,05mol
mBaSO4=0,05.233=11,65g