1: Khi x=4 thì \(B=\dfrac{3}{2-1}=3\)
2: P=A-B
\(=\dfrac{6}{x-1}+\dfrac{\sqrt{x}}{\sqrt{x}+1}-\dfrac{3}{\sqrt{x}-1}\)
\(=\dfrac{6+x-\sqrt{x}-3\sqrt{x}-3}{x-1}=\dfrac{x-4\sqrt{x}+3}{x-1}=\dfrac{\sqrt{x}-3}{\sqrt{x}+1}\)
Đúng 0
Bình luận (0)