Question

Giai bất phương trình sau   \(\dfrac{2x+2}{5}+\dfrac{3}{10}< \dfrac{3x-2}{4}\)

Answer 1

\(\dfrac{2x+2}{5}+\dfrac{3}{10}\)<\(\dfrac{3x-2}{4}\)

⇒ \(\dfrac{4\left(2x+2\right)}{20}+\dfrac{6}{20}-\dfrac{5\left(3x-2\right)}{20}\)<0

⇔\(8x+8+6-15x+10< 0\) ( vì 20>0)

⇔ \(-7x< -24\)

⇔\(x\)>\(\dfrac{24}{7}\)