\(\begin{array}{l}B = \tan {20^o}.\tan {30^o}.\tan {40^o}.\tan {50^o}.\tan {60^o}.\tan {70^o}\\ = \tan {20^0}.\tan {30^0}.\tan {40^0}.\cot \left( {{{90}^0} - {{50}^0}} \right).\cot \left( {{{90}^0} - {{60}^0}} \right).\cot \left( {{{90}^0} - {{70}^0}} \right)\\ = \tan {20^0}.\tan {30^0}.\tan {40^0}.\cot {40^0}.\cot {30^0}.\cot {20^0}\\ = \left( {\tan {{20}^0}.\cot {{20}^0}} \right).\left( {\tan {{30}^0}.\cot {{30}^0}} \right).\left( {\tan {{40}^0}.\cot {{40}^0}} \right)\\ = 1.1.1\\ = 1\end{array}\)
Chọn đáp án B.
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