Question

G=\(3+3^2+3^3+...+3^{2017}\)

Answer 1

3G=3^2+3^3+3^4+....+3^2017+3^2018

3G-G=3^2018-3

2G=3^2018-3

G=\(\dfrac{3^{2018}-3}{2}\)

Answer 2

\(G=3+3^2+3^3+...+3^{2017}\)

\(3G=3\left(3+3^2+3^3+...+3^{2017}\right)\)

\(3G=3^2+3^3+3^4+...+3^{2018}\)

\(3G-G=\left(3^2+3^3+3^4+...+3^{2018}\right)-\left(3+3^2+3^3+...+3^{2017}\right)\)

\(2G=3^{2018}-3\)

\(G=\dfrac{3^{2018}-3}{2}\)

Answer 3

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