Bài 5: Phương trình chứa ẩn ở mẫu
Các câu hỏi tương tự
Giái phương trình :
a,\(\frac{6x+1}{x^2-7x+10}+\frac{5}{x-2}=\frac{3}{x-5}\)
b,\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
c,\(\frac{1}{3-x}-\frac{1}{x+1}=\frac{x}{x-3}-\frac{\left(x-1\right)^2}{x^2-2x-3}\)
d,\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
a) frac{7x-3}{x-1}frac{2}{3}
b) frac{1}{x-2}+3frac{3-x}{x-2}
c) frac{8-x}{x-7}-8frac{1}{x-7}
d) frac{x+5}{x-5}-frac{x-5}{x+5}frac{20}{x^2-25}
e) frac{x}{2left(x-3right)}+frac{x}{2left(x+1right)}frac{2x}{left(x+1right)left(x-3right)}
f) frac{1}{x}+frac{1}{x+10}frac{1}{12}
Mong mọi người giúp đỡ ~~ __
Đọc tiếp
a) \(\frac{7x-3}{x-1}=\frac{2}{3}\)
b) \(\frac{1}{x-2}+3=\frac{3-x}{x-2}\)
c) \(\frac{8-x}{x-7}-8=\frac{1}{x-7}\)
d) \(\frac{x+5}{x-5}-\frac{x-5}{x+5}=\frac{20}{x^2-25}\)
e) \(\frac{x}{2\left(x-3\right)}+\frac{x}{2\left(x+1\right)}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
f) \(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\)
Mong mọi người giúp đỡ >~~< >__<
giải PT sau :\(\frac{3x+2}{x+4}+\frac{2x+1}{x-2}=5-\frac{x-32}{x^2+2x-8}\)
:\(\frac{x+2m}{x+3}+\frac{x-m}{x-3}=\frac{mx\left(x+1\right)}{x^2-9}\)
a)\(\frac{5}{x+7}+\frac{8}{2x+14}=\frac{3}{2}\)
b)\(\frac{x+3}{x-3}-\frac{1}{x}=\frac{3}{x\left(x-3\right)}\)
c)\(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\)
d)\(\frac{90}{x}-\frac{36}{x-36}=2\)
c)\(\frac{x}{x+1}-\frac{2x-3}{1-x}=\frac{3x^2+5}{x^2-1}\)
Giari các phương trình sau.
a. frac{1}{x}+frac{1}{x+10}frac{1}{12}
b. frac{x+3}{x-3}-frac{1}{x}frac{3}{xleft(x-3right)}
c. frac{3}{x+2}-frac{2}{x-2}+frac{8}{x^2-4}0
d. frac{3}{x+2}-frac{2}{x-3}frac{8}{left(x-3right)left(x+2right)}
e. frac{x}{2x+6}-frac{x}{2x+2}frac{3x+2}{left(x+1right)left(x+3right)}
f. frac{x}{x+1}-frac{2x-3}{1-x}frac{3x^2+5}{x^2-1}
g. frac{5}{x+7}+frac{8}{2x+14}frac{3}{2}
h. frac{x-1}{x}-frac{1}{x+1}frac{2x-1}{x^2+x}
Đọc tiếp
Giari các phương trình sau.
a. \(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\)
b. \(\frac{x+3}{x-3}-\frac{1}{x}=\frac{3}{x\left(x-3\right)}\)
c. \(\frac{3}{x+2}-\frac{2}{x-2}+\frac{8}{x^2-4}=0\)
d. \(\frac{3}{x+2}-\frac{2}{x-3}=\frac{8}{\left(x-3\right)\left(x+2\right)}\)
e. \(\frac{x}{2x+6}-\frac{x}{2x+2}=\frac{3x+2}{\left(x+1\right)\left(x+3\right)}\)
f. \(\frac{x}{x+1}-\frac{2x-3}{1-x}=\frac{3x^2+5}{x^2-1}\)
g. \(\frac{5}{x+7}+\frac{8}{2x+14}=\frac{3}{2}\)
h. \(\frac{x-1}{x}-\frac{1}{x+1}=\frac{2x-1}{x^2+x}\)
a) \(\frac{1}{2x-3}-\frac{3}{x\left(2x-3\right)}=\frac{5}{x}\)
b)\(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x\left(x-2\right)}\)
c)\(\frac{x +1}{x-2}+\frac{x-1}{x +2}=\frac{2\left(x^{2^{ }}+2\right)}{x^2-4}\)
d)(2x+3)\(\left(\frac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\frac{3x+8}{2-7x}+1\right)\)
\(\frac{x+2}{x-2}-\frac{5}{x}=\frac{8}{x^2-2x}-\frac{3}{x-1}=\frac{3x+2}{1-x^2}-\frac{4}{x+1}\)
10 tháng 2 2020 lúc 20:24
1) Giải các pt chứa ẩn ở mẫu:
a) \(\frac{x-9}{x}-\frac{x}{x-9}=0\)
b) \(\frac{x+3}{x-2}=\frac{5}{\left(x-2\right)\left(3-x\right)}\)
c) \(\frac{x}{3x-2}-\frac{x}{4x-3}=\frac{x^3}{\left(3x-2\right)\left(4x-3\right)}\)
d) \(\frac{x}{x-5}-\frac{x-5}{x}=0\)
a.\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{16}{x^2-1}\)
b.\(\frac{12}{x^2-4}-\frac{x+1}{x-2}+\frac{x+7}{x+2}=0\)
c.\(\frac{12}{8-x^3}=1+\frac{1}{x+2}\)
d.\(\frac{x+25}{2x^2-50}-\frac{x+5}{x^2-5x}=\frac{5-x}{2x^2+10x}\)
e.\(\frac{4}{x^2+2x-3}=\frac{2x-5}{x+3}-\frac{2x}{x-1}\)