Ta có : C = 12 đvC = 1,9926.10-23
\(\Rightarrow1đvC=\frac{1,9926.10^{-23}}{12}=1,6605.10^{-24}\)
a) mCl = 1,6605.10-24 . 35,5 = 5,894775.10-23 (g)
b) mH = 1,6605.10-24. 1 = 1,6605.10-24 (g)
c) mNa = 1,6605.10-24 .23 = 3,81915.10-23 (g)
a)mCl=1,66.10^-24.35.3=5,893.10^-23 (g)
b)mH=1,66.10^-24.1=1,66.10^-24 (g)
c)mNa=1,66.10^-24.23=3,818.10^-23 (g)