a) \(HgO+H_2\underrightarrow{t^o}Hg+H_2O\)
b) \(n_{HgO}=\frac{m_{HgO}}{M_{HgO}}=\frac{43,4}{217}=0,2\left(mol\right)\)
Theo PTHH, ta có: \(n_{H_2}=n_{HgO}=0,2\left(mol\right)\)
\(V_{H_2}=n_{H_2}.22,4=0,2.22,4=4,48\left(l\right)\)
c) Theo PTHH, ta có:
\(n_{Hg}=n_{HgO}=0,2\left(mol\right)\)
\(m_{Hg}=n_{Hg}.M_{Hg}=0,2.201=41,4\left(g\right)\)