a) PTPU : CuO + CO \(\rightarrow\) Cu + CO2 (1)
1mol : 1mlo : 1mol : 1mol
x mol: x mol : xmol : xmol
Fe2O3 + 3CO \(\rightarrow\) 2 Fe + 3 CO2 (2)
1mol : 3mol : 2mol : 3mol
y mol : y mol : y mol : ymol
b) Gọi nCuO = xmol , nFe2O3 = y mol ( x,y >0)
ta có : nCO2 = \(\dfrac{7,84}{22,4}\) = 0,35 mol
theo pt (1) và (2) :
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}80x+160y=20\\x+3y=0,35\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,05\\y=0,1\end{matrix}\right.\)
\(\Rightarrow\) mCuO= 0,05 . 80=4 g
mFe2O3= 0,1.160=16g
\(\Rightarrow\) %CuO = \(\dfrac{4}{20}.100\)% =20 %
%Fe2O3 = \(\dfrac{16}{20}.100\)% = 80%
