\(m_{H2O}=7,8-6=1,8\left(g\right)\)
\(n_{H2O}=\frac{1,8}{18}=0,1\left(mol\right)\)
Neste bằng nhau nên nancol bằng nhau
\(n_X=2n_{H2O}=0,2\left(mol\right)\)
\(\Rightarrow\) n mỗi ancol \(=0,1\left(mol\right)\)
Gọi 2 ancol có dạng là \(C_nH_{2n+1}OH,C_mH_{2m+1}OH\)
\(0,1.\left(14n+18\right)+0,1.\left(14m+18\right)=7,8\)
\(\Rightarrow n+m=3\)
\(\Rightarrow CH_3OH;C_2H_5OH\)