Question

Dot chay photpho trong oxi thu duoc 28,4 gam diphopho pentaoxit P₂O₅

a) Lap phuong trinh hoa hoccua phan ung?

b) Tinh khoi luong photpho va the tich O₂ o dktc tham gia phan ung

Answer 1

a) PTHH: \(4P+5O_2 \underrightarrow{t^o} 2P_2O_5\)

b) Ta có: \(n_{P_2O_5}=\dfrac{28,4}{142}=0,2\left(mol\right)\)

\(\Rightarrow\left\{{}\begin{matrix}n_P=0,4mol\\n_{O_2}=0,5mol\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m_P=0,4\cdot31=12,4\left(g\right)\\V_{O_2}=0,5\cdot22,4=11,2\left(l\right)\end{matrix}\right.\)