\(X+O_2\overset{t^0}{\rightarrow}XO_2\)
\(\overline{M_{hh}}=29.1,7655\approx51,2\)
- Áp dụng định luật BTKL:\(m_{Sau}=\)mtrước=m+m1
- Bảo toàn oxi: \(n_{XO_2}+n_{O_2\left(dư\right)}=n_{O_2\left(bđ\right)}=\dfrac{m_1}{32}mol\)
\(\overline{M_{hh}}=\dfrac{m_{hh}}{n_{hh}}=\dfrac{m+m_1}{\dfrac{m_1}{32}}=51,2\rightarrow\dfrac{m}{m_1}=0,6\)