Đặt CTPT X là \(C_nH_{2n-2}\)
=>\(\frac{2,7}{14n-2}=\frac{4,48}{22,4}\Leftrightarrow\frac{2,7}{14n-2}=0,2\)
\(\Rightarrow n=4\)
CTPT:\(C4H6\)
\(C_nH_{2n-2}+\left(\frac{3n-1}{2}\right)O_2\rightarrow nCO_2+\left(n-1\right)H_2O\)
Ta có :
\(n_{CO2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
\(\Rightarrow n_{CnH2n-2}=\frac{0,2}{n}\left(mol\right)\)
\(M_{CnH2n-2}=\frac{2,7}{\frac{0,2}{n}}=13,5n\)
\(14n-2=13,5n\Rightarrow n=4\)
Vậy CTPT là C4H6
