pt C2H6O+3O2\(\rightarrow\)2CO2 +3H2O
ta có n C2H6O =\(\dfrac{18,4}{46}\)=0,4 mol
theo pt nCO2 =2nC2H6O=0,8 mol
suy ra mCO2 =0,8*44=35,5 g
theo pt nH20=3n C2H6O =1,2 mol suy ra m H2O =21,6 g
pt điều chế axit axetic
C2H60+02\(\rightarrow\)CH3COOH+H2O
THEO PT nCH3COOH =nC2H6O =0,4mol
suy ra n CH3COOH=60*0,4=24g