-Đặt CTPT: CxHyO
CxHyO+(\(x+\dfrac{y}{4}-\dfrac{1}{2}\))O2\(\rightarrow\)xCO2+\(\dfrac{y}{2}H_2O\)
\(n_{O_2}=\dfrac{19,2}{32}=0,6mol\)
\(\dfrac{n_{CO_2}}{n_{H_2O}}=\dfrac{2x}{y}=\dfrac{0,4}{0,5}=0,8\)\(\rightarrow\)2x=0,8y\(\rightarrow\)y=2,5x
\(\dfrac{n_{O_2}}{n_{CO_2}}=\dfrac{x+\dfrac{y}{4}-\dfrac{1}{2}}{x}=\dfrac{0,6}{0,4}=1,5\)
\(\rightarrow\)x+\(\dfrac{2,5x}{4}-\dfrac{1}{2}\)=1,5x\(\rightarrow\)0,125x=0,5\(\rightarrow\)x=4\(\rightarrow\)y=2,5.4=10
CTPT: C4H10O hay C4H9OH