\(n_X=\dfrac{0.112}{22.4}=0.005\left(mol\right)\)
\(CT:C_nH_{2n+2}\)
\(m_{tăng}=m_{H_2O}=0.36g\)
\(\Rightarrow n_{_{ }H_2O}=\dfrac{0.36}{18}=0.02\left(mol\right)\)
\(BTNTH:\)
\(\left(2n+2\right)\cdot n_X=2\cdot n_{H_2O}\)
\(\Leftrightarrow\left(2n+2\right)\cdot0.005=2\cdot0.02\)
\(\Leftrightarrow n=3\)
\(CTPT:C_3H_6\)
\(CH_3-CH_2-CH_3\)