\(n_{CO_2}=n_{H_2O}\)
\(\Leftrightarrow\dfrac{m+2.8}{44}=\dfrac{m-2.4}{18}\)
\(\Leftrightarrow m=6\)
\(n_{CO_2}=n_{H_2O}=\dfrac{6+2.8}{44}=0.2\left(mol\right)\)
\(n_{este}=\dfrac{6-0.2\cdot12-0.2\cdot2}{32}=0.1\)
\(n=\dfrac{0.2}{0.1}=2\)
\(CT:C_2H_4O_2\)