\(\frac{{2x + 3}}{{x - 4}} + 2 = \frac{1}{{x - 3}}\)
ĐKXĐ: \(\left\{ {\begin{array}{*{20}{c}}{x - 4 \ne 0}\\{x - 3 \ne 0}\end{array}} \right.\) suy ra \(\left\{ {\begin{array}{*{20}{c}}{x \ne 4}\\{x \ne 3}\end{array}} \right.\)
Đáp án C.
Đúng 0
Bình luận (0)