Ôn tập toán 6
Các câu hỏi tương tự
\(\dfrac{1+\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{7}+....+\dfrac{1}{97}+\dfrac{1}{99}}{\dfrac{1}{1x99}+\dfrac{1}{3x97}+\dfrac{1}{5x95}+...+\dfrac{1}{97x3}+\dfrac{1}{99x1}}\)
Tính giá trị biểu thức:
\(\dfrac{1+\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{7}+...+\dfrac{1}{97}+\dfrac{1}{99}}{\dfrac{1}{1\cdot99}+\dfrac{1}{3\cdot97}+\dfrac{1}{5\cdot95}+...+\dfrac{1}{97\cdot3}+\dfrac{1}{99\cdot1}}\)
Ruat gọn biểu thức:
T=\(\left(\dfrac{1}{2}+1\right).\left(\dfrac{1}{3}+1\right).\left(\dfrac{1}{4}+1\right).....\left(\dfrac{1}{98}+1\right).\left(\dfrac{1}{99}+1\right)\)
Rút gọn \(C=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{99}}+\dfrac{1}{8.3^{99}}\)
Rút gọn biểu thức sau:
T = (\(\dfrac{1}{2}+1\)) . (\(\dfrac{1}{3}+1\)) . (\(\dfrac{1}{4}+1\)) ... . (\(\dfrac{1}{98}+1\)) . (\(\dfrac{1}{99}+1\)).
tính nhanh
2155-(174+2155)+(-68+174)
2.dfrac{3}{7}left(dfrac{2}{9}-1dfrac{3}{7}right)-dfrac{5}{3}:dfrac{1}{9}
left(1-dfrac{1}{2}right)left(1-dfrac{1}{3}right)left(1-dfrac{1}{4}right)left(1-dfrac{1}{5}right)
left(dfrac{377}{-231}-dfrac{123}{89}+dfrac{34}{791}right).left(dfrac{1}{6}-dfrac{1}{8}-dfrac{1}{24}right)
chứng tỏ phân số sau tối giản vs mọi số tự nhiên ndfrac{n+1}{2n+3}
Đọc tiếp
tính nhanh
2155-(174+2155)+(-68+174)
2.\(\dfrac{3}{7}\left(\dfrac{2}{9}-1\dfrac{3}{7}\right)-\dfrac{5}{3}:\dfrac{1}{9}\)
\(\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)\left(1-\dfrac{1}{5}\right)\)
\(\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right).\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{24}\right)\)
chứng tỏ phân số sau tối giản vs mọi số tự nhiên n\(\dfrac{n+1}{2n+3}\)
tính tổng
Sdfrac{1}{1cdot2cdot3}+dfrac{1}{2cdot3cdot4}+dfrac{1}{3cdot4cdot5}+...+dfrac{1}{ncdotleft(n+1right)cdotleft(n+2right)}
A1+dfrac{1}{3}+dfrac{1}{5}+dfrac{1}{7}+...+dfrac{1}{99}
B dfrac{1}{2}+dfrac{1}{3}+dfrac{1}{4}+...dfrac{1}{100}
Cdfrac{99}{1}+dfrac{98}{2}+dfrac{97}{3}+...+dfrac{1}{99}
Đọc tiếp
tính tổng
S=\(\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+\dfrac{1}{3\cdot4\cdot5}+...+\dfrac{1}{n\cdot\left(n+1\right)\cdot\left(n+2\right)}\)
A=1+\(\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{7}+...+\dfrac{1}{99}\)
B= \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...\dfrac{1}{100}\)
C=\(\dfrac{99}{1}+\dfrac{98}{2}+\dfrac{97}{3}+...+\dfrac{1}{99}\)
Cho A=\(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{99}+\dfrac{1}{100}}{\dfrac{99}{1}+\dfrac{98}{2}+\dfrac{97}{3}+...+\dfrac{2}{98}+\dfrac{1}{99}}\)
Tính A
Rút gọn biểu thức D=\(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right)....\left(1-\dfrac{1}{2015}\right)\)