Câu hỏi của Thư Ngọc

Question

dẫn 10g hỗn hợp gồm etan, axetilen vào dd brom 16% thu được 51,9g tetrabrometan và có V lít khí thoát ra ở đktc
a. tính % theo khối lượng mỗi khí có trong hh ban đầu
b. tính V
c. t...

Hung nguyen · Accepted Answer

a/ $C_2H_2\left(0,15\right)+2Br_2\left(0,3\right)\rightarrow C_2H_2Br_4\left(0,15\right)$

$n_{C_2H_2Br_4}=\dfrac{51,9}{346}=0,15\left(mol\right)$

$\Rightarrow m_{C_2H_2}=0,15.26=3,9\left(g\right)$

$\Rightarrow\left\{{}\begin{matrix}\%C_2H_2=\dfrac{3,9}{10}.100\%=39\%\\%C_2H_6=100\%-39\%=61\%\end{matrix}\right.$

b/ $m_{C_2H_6}=10-3,9=6,1\left(g\right)$

$\Rightarrow n_{C_2H_6}=\dfrac{6,1}{30}=\dfrac{61}{300}\left(mol\right)$

$\Rightarrow V_{C_2H_6}=\dfrac{61}{300}.22,4=4,56\left(l\right)$

c/ $m_{Br_2}=0,3.160=48\left(g\right)$

$\Rightarrow m_{ddBr_2}=\dfrac{48}{16\%}=300\left(g\right)$Câu trả lời: a/ $C_2H_2\left(0,15\right)+2Br_2\left(0,3\right)\rightarrow C_2H_2Br_4\left(0,15\right)$