\(\frac{x^2+y^2+2xy-1}{x^2-y^2+2x+1}=\frac{\left(x+y\right)^2-1}{\left(x+1\right)^2-y^2}=\frac{\left(x+y-1\right).\left(x+y+1\right)}{\left(x+1-y\right).\left(x+1+y\right)}=\frac{x+y-1}{x-y+1}\)
Bài này áp dụng HĐT thứ 3 : \(a^2-b^2=\left(a-b\right)\left(a+b\right)\).