\(2^{2^{2n}}+5\)
\(=2^{4n}+5\)
\(=2^{\left(3+1\right)n}+5\)
\(=2^{B\left(3+1\right)}+5\)
\(=2^{3k+1}+5\)
\(=8^k\times2-2+7\)
\(=2\left(8^k-1^k\right)+7\)
\(8^k-1^k⋮8-1=7\Rightarrow2\left(8^k-1^k\right)⋮7\)\(7⋮7\)Vậy \(2^{2^{2n}}+5⋮7\)
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