Question

cho \(x\ne0\) \(n\ne0\) và \(\left(x-\dfrac{1}{x}\right):\left(x+\dfrac{1}{x}\right)=n\)

tính K=\(\left(x^2+\dfrac{1}{x^2}\right):\left(x^2+\dfrac{1}{x^2}\right)\)