b: \(\overrightarrow{CO}=\left(1;-2\right)\)
\(\overrightarrow{AB}=\left(-4;-2\right)\)
Vì \(\overrightarrow{CO}\cdot\overrightarrow{AB}=0\)
nên CO\(\perp\)AB
\(\overrightarrow{AC}=\left(-3;1\right)\)
\(\overrightarrow{AB}=\left(-4;-2\right)=\left(-2;-1\right)=\left(2;1\right)\)
\(\overrightarrow{BC}=\left(1;3\right)\)
Vì \(\overrightarrow{AC}\cdot\overrightarrow{BC}=0\)
nên ΔCAB vuông tại C